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MediumGraphsAI interview only

Clone Graph

Asked atmetagoogleamazonbloomberguber

01 · Problem

Given a reference of a node in a connected undirected graph, return a deep copy (clone) of the graph.

Each node in the graph contains a value (val) and a list of its neighbors (neighbors).

class Node {
    public int val;
    public List<Node> neighbors;
}

Test case format:

For simplicity, each node's value is the same as the node's index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.

An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.

The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.

02 · Examples

Example 01
Input
adjList = [[2,4],[1,3],[2,4],[1,3]]
Output
[[2,4],[1,3],[2,4],[1,3]]

There are 4 nodes forming a cycle: 1-2-3-4-1. Each node is cloned with its neighbors correctly referencing the new cloned nodes, not the originals.

Example 02
Input
adjList = [[]]
Output
[[]]

The graph has a single node with val = 1 and no neighbors. The clone is a new node with val = 1 and an empty neighbors list.

Example 03
Input
adjList = []
Output
[]

The graph is empty (null input), so the output is also null/empty.

03 · Constraints

  • 01The number of nodes in the graph is in the range [0, 100].
  • 021 <= Node.val <= 100
  • 03Node.val is unique for each node.
  • 04There are no repeated edges and no self-loops in the graph.
  • 05The graph is connected and all nodes can be visited starting from the given node.

04 · Optimal complexity

Time
O(V + E)
Space
O(V)
05 · Two ways to work on it

Practice it alone or rehearse it as an interview.

Practice Mode gives you an editor and test runs, nothing else. AI Interview Mode puts a voice interviewer on the other side, adds a clock, and ends with a scored summary of the round.