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Find Median from Data Stream
Asked atamazongooglemetamicrosoftapplebloombergnetflixgoldman-sachs
01 · Problem
The median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value, and the median is the mean of the two middle values.
- For example, for
arr = [2,3,4], the median is3. - For example, for
arr = [2,3], the median is(2 + 3) / 2 = 2.5.
Implement the MedianFinder class:
MedianFinder()initializes theMedianFinderobject.void addNum(int num)adds the integernumfrom the data stream to the data structure.double findMedian()returns the median of all elements so far. Answers within10^-5of the actual answer will be accepted.
02 · Examples
Example 01
Input
operations = ["MedianFinder", "addNum", "addNum", "findMedian", "addNum", "findMedian"] arguments = [[], [1], [2], [], [3], []]
Output
[null, null, null, 1.5, null, 2.0]
After adding 1 and 2, the median is (1+2)/2 = 1.5. After adding 3, the sorted list is [1,2,3] and the median is 2.0.
Example 02
Input
operations = ["MedianFinder", "addNum", "findMedian"] arguments = [[], [5], []]
Output
[null, null, 5.0]
With only one element, the median is that element itself: 5.0.
Example 03
Input
operations = ["MedianFinder", "addNum", "addNum", "addNum", "addNum", "findMedian"] arguments = [[], [1], [2], [3], [4], []]
Output
[null, null, null, null, null, 2.5]
The sorted list is [1,2,3,4]. With an even count, the median is (2+3)/2 = 2.5.
03 · Constraints
- 01-105 <= num <= 105
- 02There will be at least one element in the data structure before calling findMedian
- 03At most 5 * 104 calls will be made to addNum and findMedian
04 · Optimal complexity
- Time
- O(log n) per addNum, O(1) per findMedian
- Space
- O(n)
05 · Two ways to work on it
Practice it alone or rehearse it as an interview.
Practice Mode gives you an editor and test runs, nothing else. AI Interview Mode puts a voice interviewer on the other side, adds a clock, and ends with a scored summary of the round.