Lowest Common Ancestor of a Binary Search Tree
01 · Problem
Given a binary search tree (BST), find the lowest common ancestor (LCA) node of two given nodes in the BST.
According to the definition of LCA on Wikipedia: "The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself)."
02 · Examples
6
/ \
2 8
/ \ / \
0 4 7 9
/ \
3 5root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8
6
The LCA of nodes 2 and 8 is 6. Node 2 is in the left subtree and node 8 is in the right subtree, so the root (6) is their lowest common ancestor.
6
/ \
2 8
/ \ / \
0 4 7 9
/ \
3 5root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4
2
The LCA of nodes 2 and 4 is 2. Node 4 is a descendant of node 2, and a node can be a descendant of itself according to the LCA definition.
root = [2,1], p = 2, q = 1
2
The root node 2 is the ancestor of node 1, and since a node is its own descendant, the LCA is 2.
03 · Constraints
- 01The number of nodes in the tree is in the range [2, 105].
- 02-109 <= Node.val <= 109
- 03All Node.val are unique.
- 04p != q
- 05p and q will exist in the BST.
04 · Optimal complexity
- Time
- O(h)
- Space
- O(1)
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